Newtons law of cooling,Determination of specific heat of liquid by the method of coolin(part-3)
Projectile Motion” MCQS(part-2)
1. A body of mass m, projected at an angle of θ from the ground with an initial velocity of v, acceleration due to gravity is g, what is the maximum horizontal range covered? a) R = v2 (sin 2θ)/g b) R = v2 (sin θ)/2g c) R = v2 (sin 2θ)/2g d) R = v2 (sin θ)/g 2. A body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s2, what is the maximum horizontal range covered? a) 54.13 m b) 49 m c) 49.16 m d) 60 m 3. A body of mass 10 kg, projected at an angle of 30° from the ground with an initial velocity of 5 m/s, acceleration due to gravity is g = 10 m/s2, what is the time of flight? a) 0.866s b) 1.86 s c) 1.96 s d) 1.862s 4. On calculating which of the following quantities, the mass of the body has an effect in simple projectile motion? a) Velocity b) Force c) Time of flight d) Range 5. A ball of mass 100 g, projected at an angle of 30° from the ground with an initial velocity of 11 m/s, acceleration due to ...
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